After more 2 000 000 (two million) views on forum for 1.5.0.x development versions... and 1.6.1.0, 1.6.3.0-dev versions
A new stable version, UltraVNC 1.6.4.0 and UltraVNC SC 1.6.4.0 have been released: https://forum.uvnc.com/viewtopic.php?t=38095
Feedback is always welcome

2025-12-05: Celebrating the 23th anniversary of the UltraVNC (26th anniversary since the laying of the foundation stone): https://forum.uvnc.com/viewtopic.php?t=38130

2025-12-03: Could you please complete our poll/survey? Renaming UltraVNC files and service to be more clear: https://forum.uvnc.com/viewtopic.php?t=38128
There was a problem to vote, it is solved now! Thanks in advance!

2025-12-02: We need help: English Wikipedia UltraVNC page has been requested to deletion: https://forum.uvnc.com/viewtopic.php?t=38127
Any help is welcome to improve the UltraVNC page and/or to comment on the Wikipedia Talk page

2025-05-06: Forum password change request: https://forum.uvnc.com/viewtopic.php?t=38078

2023-09-21: Important: Please update to latest version before to create a reply, a topic or an issue: https://forum.uvnc.com/viewtopic.php?t=37864

Development: UltraVNC development is always here... Any help is welcome
Feedback is welcome

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*Newbie* MS Logon II

Should you have problems with the MS-Logon plugin? Here is the place to look for help or report issues
Post Reply
moviebuff03
Posts: 1
Joined: 2006-05-27 14:08

*Newbie* MS Logon II

Post by moviebuff03 »

Ok, I am still a bit confused with all this...

I have setup VNC on two computers (SERVER and PVR). Now I can access the server from the PVR as a I have an actual windows logon account, but don't know how to setup VNC so it will logon to the PVR as I simply use the Administrator without a password. This is automatic when Windows starts up.

When I am prompted by VNC for a username and password the connection fails.

Any ideas?

Thanks
Marscha
100
100
Posts: 464
Joined: 2004-05-14 06:48

Post by Marscha »

sounds like your PVR is XP Home (or something similar).
Maybe you can just use classic authentication in this case.
Post Reply